5x^2-20x+96=0

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Solution for 5x^2-20x+96=0 equation:


Simplifying
5x2 + -20x + 96 = 0

Reorder the terms:
96 + -20x + 5x2 = 0

Solving
96 + -20x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
19.2 + -4x + x2 = 0

Move the constant term to the right:

Add '-19.2' to each side of the equation.
19.2 + -4x + -19.2 + x2 = 0 + -19.2

Reorder the terms:
19.2 + -19.2 + -4x + x2 = 0 + -19.2

Combine like terms: 19.2 + -19.2 = 0.0
0.0 + -4x + x2 = 0 + -19.2
-4x + x2 = 0 + -19.2

Combine like terms: 0 + -19.2 = -19.2
-4x + x2 = -19.2

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -19.2 + 4

Reorder the terms:
4 + -4x + x2 = -19.2 + 4

Combine like terms: -19.2 + 4 = -15.2
4 + -4x + x2 = -15.2

Factor a perfect square on the left side:
(x + -2)(x + -2) = -15.2

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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